Thursday, October 10, 2013

Aerocarnival

4)It took MegaTech, Inc. 100,000 labor-hours to nurture the branch of several oil bore rigs for charged exploration. Your company, Natural Resources, Inc. has agreed to purchase the fifth oil oil production rig from their manufacturing yard. Assume that MegaTech experiences a learning come in of 80%. At a labor rate of $35 per hour, what should you, as the purchasing agent expect to pay for the fifth entire? Remember, the simplified formula for calculating learning rate banner is given as: TN = T1C Where, TN = Time needed to produce the nth unit of measurement T1= Time needed to produce the first unit C= acquirement curved shape coefficient Answer The hold over lists the fourth unit learning curve coefficient as .596, anticipate a learning rate of 80%. Using the formula, to produce the fifth unit takes: T5 = (100,000) (.596) = 59,600 hours To find the personify, calculate the hours by the hourly rate: = (59,600) ($35 per hour) = $2,086,000 6)Suppose that you ar the assigning costs to a major cat to be undertaken by your firm, DynoSoft Applications, this year. One extra code process involves some(prenominal) labor hours, but highly unembellished work. You anticipate a total of 200,000 labor hours to complete the first grummet of the coding and a learning curve rate of 70%.
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You be attempting to estimate the cost of the twentieth eyelet of this coding sequence. establish on the above information and at a $60 per hour labor rate, what would you expect to compute as the cost of the twentieth cringle? The fortieth iteration? Answer T20=T1C =(200 ,000) (.214) =42,800 hours T40=T1C =! (200,000) (.150) =30,000 hours The costs for the twentieth and 40th iterations atomic bend 18 found as: 20th iteration: (42,800 hours) ($60 per hour) =$2,568,000 40th iteration: (30,000 hours) ($60 per hour) =$1,800,000 7)Assume you are a project cost engineer calculating the cost of a repetitive activity for your project. There are a total of 20...If you neediness to get a full essay, straddle it on our website: BestEssayCheap.com

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